news system problem : antal news på forsiden

hvordan gør jeg så kun de 5 nyeste nyheder bliver vist i mit news system?

SCRIPT:

<?php

                   
                   
                    // instantiate variables (edit as necessary)
                    $host = ($host) ? $host : "localhost";
                    $user = ($user) ? $user : "";
                    $pwd = ($pwd)  ? $pwd  : "";

                    $link = mysql_connect($host,$user,$pwd) or die("Could not connect to Host.");

                    $field = nl2br($field);
                    echo $field;
                   
          $db="";
          $link = mysql_connect($host,$user,$pwd) or die("Could not connect to Host.");
          if (! $link)
          die("kunne ikke oprette forbindelse til MySQL");
          mysql_select_db($db , $link)
          or die("kunne ikke åbne $db: ".mysql_error());
                    $result = mysql_query( "SELECT * FROM news ORDER BY newstime DESC" )
                    or die("SQL FEJL: ".mysql_error());
                    $num_rows = mysql_num_rows($result);
          print "<table border=0 cellspacing=0 bordercolor=#000000>\n";
          while ($get_info = mysql_fetch_row($result)){
          print "<tr>\n";
          foreach ($get_info as $field) ?>
                   
                    <?php


$smilies=array(

":)" => "<img src='smilies/happy.gif' border=0>",

":(" => "<img src='smilies/sad.gif' border=0>",

":D" => "<img src='smilies/biggrin.gif' border=0>",

":P" => "<img src='smilies/tongue.gif' border=0>",

":p" => "<img src='smilies/tongue.gif' border=0>",

";)" => "<img src='smilies/wink.gif' border=0>",

";D" => "<img src='smilies/biggrin.gif' border=0>",

);



$field = str_replace(array_keys($smilies),array_values($smilies),$field);?>
                   
                    <td valign="top" align="center"><font face="Verdana" size="1"/><?$field = nl2br($field); echo $field;?><hr width="510" noshade size="1" color="#000000"></font></td>
                    <?
          print "</tr>\n";
          }
          print "</table>\n";
          mysql_close($link);
                   
          ?>