Langsomt script m.m.

Hej!
Jeg sidder og laver en side der skal kunne uploade og lave en html-side. Det virker også fint, men scriptet til at uploade med er enormt langsomt og filer over 250 kb tager evigheder eller lykkedes slet til. Scriptet er hygget direkte fra Microsoft. Kan det gøres hurtigere...evt. ved at skære noget væk???
Et andet spørgsmål er, hvilke rettigheder den mappe scriptet ligger i på serveren skal have for at måtte oprette en ny fil??

Herunder er scriptet:
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<%
'Adjust this depending on the size of the files you'll
'be expecting; longer timeout for larger files!
Server.ScriptTimeout = 6500

'Dim overskrift, frist, evt
'overskrift = Request.Form("overskrift")
'frist = Request.Form("frist")
'evt = Request.Form("evt")

Const ForWriting = 2
Const TristateTrue = -1
CrLf = Chr(13) & Chr(10)

'This function retreives a field's name
Function GetFieldName(infoStr)
    sPos = InStr(infoStr, "name=")
    EndPos = InStr(sPos + 6, infoStr, Chr(34) & ";")
    If EndPos = 0 Then
        EndPos = inStr(sPos + 6, infoStr, Chr(34))
    End If
    GetFieldName = Mid(infoStr, sPos + 6, endPos - _
        (sPos + 6))
End Function

'This function retreives a file field's filename
Function GetFileName(infoStr)
    sPos = InStr(infoStr, "filename=")
    EndPos = InStr(infoStr, Chr(34) & CrLf)
    GetFileName = Mid(infoStr, sPos + 10, EndPos - _
        (sPos + 10))
End Function

'This function retreives a file field's MIME type
Function GetFileType(infoStr)
    sPos = InStr(infoStr, "Content-Type: ")
    GetFileType = Mid(infoStr, sPos + 14)
End Function

'Yank the file (and anything else) that was posted
PostData = ""
Dim biData
biData = Request.BinaryRead(Request.TotalBytes)
'Careful! It's binary! So, let's change it into
'something a bit more manageable.
For nIndex = 1 to LenB(biData)
    PostData = PostData & Chr(AscB(MidB(biData,nIndex,1)))
Next

'Having used BinaryRead, the Request.Form collection is
'no longer available to us. So, we have to parse the
'request variables ourselves!
'First, let's find that encoding type!
ContentType = Request.ServerVariables( _
    "HTTP_CONTENT_TYPE")
ctArray = Split(ContentType, ";")
'File posts only work well when the encoding is
'"multipart/form-data", so let's check for that!
If Trim(ctArray(0)) = "multipart/form-data" Then
    ErrMsg = ""
    ' grab the form boundary...
    bArray = Split(Trim(ctArray(1)), "=")
    Boundary = Trim(bArray(1))
    'Now use that to split up all the variables!
    FormData = Split(PostData, Boundary)
    'Extract the information for each variable and its data
    Dim myRequest, myRequestFiles(9, 3)
    Set myRequest = CreateObject("Scripting.Dictionary")
    FileCount = 0
    For x = 0 to UBound(FormData)
        'Two CrLfs mark the end of the information about
        'this field; everything after that is the value
        InfoEnd = InStr(FormData(x), CrLf & CrLf)
        If InfoEnd > 0 Then
            'Get info for this field, minus stuff at the end
            varInfo = Mid(FormData(x), 3, InfoEnd - 3)
            'Get value for this field, being sure to skip
            'CrLf pairs at the start and the CrLf at the end
            varValue = Mid(FormData(x), InfoEnd + 4, _
                Len(FormData(x)) - InfoEnd - 7)
            'Is this a file?
            If (InStr(varInfo, "filename=") > 0) Then
                'Place it into our files array
                '(While this supports more than one file
                'uploaded at a time we only consider the
                'single file case in this example)
                myRequestFiles(FileCount, 0) = GetFieldName( _
                    varInfo)
                myRequestFiles(FileCount, 1) = varValue
                myRequestFiles(FileCount, 2) = GetFileName( _
                    varInfo)
                myRequestFiles(FileCount, 3) = GetFileType( _
                    varInfo)
                FileCount = FileCount + 1
            Else
                'It's a regular field
                myRequest.add GetFieldName(varInfo), varValue
            End If
        End If
    Next
Else
    ErrMsg = "Wrong encoding type!"
End If

'Save the actual posted file
'If supporting more than one file, turn this into a loop!

Set lf = server.createObject("Scripting.FileSystemObject")
If myRequest("filename") = "original" Then
    'Use the filename that came with the file
    'At this point, you need to determine what sort of
    'client sent the file. Macintoshes only send the file
    'name, with no path information, while Windows clients
    'send the entire path of the file that was selected
    BrowserType = UCase(Request.ServerVariables( _
        "HTTP_USER_AGENT"))
    If (InStr(BrowserType, "WIN") > 0) Then
        'It's Windows; yank the filename off the end!
        sPos = InStrRev(myRequestFiles(0, 2), "\")
        fName = Mid(myRequestFiles(0, 2), sPos + 1)
    End If
    If (InStr(BrowserType, "MAC") > 0) Then
        'It's a Mac. Simple.
        '(Mac filenames can contain characters that are
        'illegal under Windows, so look out for that!)
        fName = myRequestFiles(0, 2)
    End If
    'If your upload path is different, set that here
    FilePath = "./" & fName
Else
    'Use the user-specified filename instead
    'If your upload path is different, set that here
    FilePath = "./" & myRequest("userSpecifiedName")
End If
SavePath = Server.MapPath(FilePath)
Set SaveFile = lf.CreateTextFile(SavePath, True)
SaveFile.Write(myRequestFiles(0, 1))
SaveFile.Close

'IIS may hang if you don't explicitly return SOMETHING.
'So, redirect to another page or provide some kind of
'feedback below...
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Her slutter scriptet.