hvorfor tager den ikke dagen i dag med
hvorfor tager den ikke dagen i dag med ??den ødelægger designet hvis der er en dag hvor grafen er lang
$sql = mysql_query("select dato,antal from info0 where sideID = '".$_GET['id']."' ORDER BY dato desc LIMIT 0,30");
$numrowsd = mysql_num_rows($sql);
$row2 = mysql_fetch_array($sql);
?>
<table border="0" width="100%" cellspacing="0" cellpadding="0">
<tr>
<td width="100%">
<font face="Verdana" size="2" color="#000000"><b>Unikke besøgende fordelt på dage<hr></b></font>
</td>
</tr>
<tr>
<td width="100%">
<table border="0" width="100%" cellspacing="0" cellpadding="0">
<?PHP
if($row2['antal']== '0'){
?>
<tr>
<td width="590" colspan="3">
<p align="center"><b><font face="Verdana" size="1">Der er
ingen statistik tilgængelig</font></b></td>
</tr>
<?PHP
}
?>
<tr>
<td width="100"><font face="Verdana" size="2"><b>Dato</b></font></td>
<td width="90"><font face="Verdana" size="2"><b>Antal</b></font></td>
<td width="400"><font face="Verdana" size="2"><b>Graf</b></font></td>
</tr>
<?PHP
while($row = mysql_fetch_array($sql)){
$color = "E6E6E6";
$y = '0';
while($row['antal'] > $y ){
$y = $row['antal'];
$y++;
}
$b = ($row['antal'] / $y * '100' - $numrowsd);
$theDate = $row['dato'];
?>
<tr>
<td width="100" bgcolor="#<?PHP echo "".$color.""; ?>"><font size="1" face="Verdana"><a href="index.php?go=stats&id=<?PHP echo "".$_GET['id']."";?>&type=time&dato=<?PHP echo "".$theDate.""; ?>"><?PHP echo "".$row['dato'].""; ?></a></font></td>
<td width="90" bgcolor="#<?PHP echo "".$color.""; ?>"><font face="Verdana" size="1"><?PHP echo "".$row['antal'].""; ?></font></td>
<td width="400" bgcolor="#<?PHP echo "".$color.""; ?>"><font face="Verdana" size="1"><img border="0" src="gfx/graf.gif" width="<?PHP echo"".$b.""; ?>" height="10"></font></td>
</tr>
<?PHP
if($color = "E6E6E6"){
$color = "FFFFFF";
}else{
$color = "E6E6E6";
}
}
?>
