String Sorter

You need 3 fields that the getters can return.

And then you need the constructor to set those 3 fields.

The simplest solution is probably just to use if statements that compare the strings.

Can you please send me the solution...using if statements..

You will not learn much by me giving you the solution.

You can approach it either with 6 if's each covering a case or by nesting if's.

I think the first would be the easiest.

Give it a try.

public class StringSet
    {
   
    public StringSet(String    string1, String string2, String string3)
    {
//        if(str1.compareTo(str2)<0 && str1.compareTo(str3)<0)
//            Minimum = str1;
//        else if(str1.compareTo(str2)>0 && str1.compareTo(str3)>0)
//            Maximum = str1;   
//        else if(str2.compareTo(str1)<0 && str2.compareTo(str3)<0)
//            Minimum = str2;
//        else if(str2.compareTo(str1)>0 && str2.compareTo(str3)>0)
//            Maximum = str2;   
//        else if(str3.compareTo(str1)<0 && str3.compareTo(str2)<0)
//            Minimum = str3;
//        else if(str3.compareTo(str1)>0 && str3.compareTo(str2)>0)
//            Maximum = str3;   
//        else
//            Maximum = "Number not found";   
               
        // Compare string1 with string3
        if(string1.compareTo(string3) < 0)
        {
        Minimum = string1;
        }
        else
        {
        if(string1.compareTo(string3) > 0)
        {
        Maximum = string1;
        }
        else
        {
        Middle = string1;
        }
        }
        if(string2.compareTo(string1) < 0)
        {
        Minimum = string2;
        }
        else
        {
        if(string2.compareTo(string1) > 0)
        {
        Maximum = string2;
        }
        else
        {
        Middle = string2;
        }
        }
        if(string2.compareTo(string3) < 0)
        {
        Minimum = string2;
        }
        else
        {
        if(string2.compareTo(string3) > 0)
        {
        Maximum = string2;
        }
        else
        {
        Middle = string3;
        }
        }               
           
           
    }
   
    public String getSmallest()
    {
        return Minimum;
    }
   
   
    public String getLargest()
    {
        return Maximum;
    }
   
   
   
   
    private String Minimum;
    private String Maximum;
    private String Middle;
    }
This is what i have so far...

if(str1.compareTo(str2) < 0 && str1.compareTo(str3) < 0 && str2.compareTo(str3) < 0) {
    minimum = str1;
    middle = str2;
    maximum = str3;
} else if(

Does'nt work...output is null for all values...

Can you post the complete code that gives null for all values?

public class StringSet
    {
   
    public StringSet(String    string1, String string2, String string3)
    {
               
    if(string1.compareTo(string2) < 0 && string1.compareTo(string3) < 0 && string2.compareTo(string3) < 0)
        {
            Minimum = string1;
            Middle = string2;
            Maximum = string3;
        }        


   
    public String getSmallest()
    {
        return Minimum;
    }
   
   
    public String getLargest()
    {
        return Maximum;
    }
   
   
       
    public String getMiddle()
    {
        return Middle;
    }
   
    private String Minimum;
    private String Maximum;
    private String Middle;
    }

------------------------------

import java. util.Scanner;
/**
This is program sorts three strings.
*/
public class StringSort
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.println("Please enter three strings:");
String str1 = in.nextLine();
String str2 = in.nextLine();
String str3 = in.nextLine();
StringSet s = new StringSet(str1, str2, str3);
System.out.println("The inputs in sorted order are:\n"
+ s.getSmallest() + "\n"
+ s.getMiddle() + "\n"
+ s.getLargest());   
}
}

The code works fine for the particular case described in the if statement.

So you just need 5 more if statements!

Thanks a lot it works fine...

Then I will drop a real answer.

Yes..No prbs at all..
I've one more question shall i post it here or in a new question..