løse denne kode

Er der en der kan knække denne kode for mig
mvh vardepigen

#include <stdio.h>


int N[] = {1,2,3,4,5,6,7};

int E[] = {9,8,7,6,5,4,0x3};

int i = 0;

int main(void)

{

for(i=0;i<=6;i++){

N[i] = N[i] * 3;

if(N[i] > 9){
do{

N[i] = N[i]-10;
}while(N[i]>9);

}

if(E[i]>8){
E[i] = E[i]-1;

}else{
E[i] = E[i]+1;

}
   
if(E[i] == 6){

E[i] = 7;
}

}

printf("\n");
printf("Du finder cachen her:");
printf("\n");

printf("N %d%d %d%d.%d%d%d",N[4],N[4],N[3],N[5],N[0],N[4]-N[6],N[0]);

printf("\n");
printf("E %d%d%d %d%d.%d%d%d",0,0,E[0],E[4]-E[5],E[3],E[4]-5,E[1]-E[0],E[4]);

printf("\n");

return 0;
}