java.lang.IllegalArgumentException: Object: dk.whatueat.JPA.Bruger[ id=null ] is not a known entity type.

Hvordan ser klassen dk.whatueat.JPA.Bruger ud?

Den er autogenereret af netbeans fra databasen..

/*
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package dk.whatueat.model;

import java.io.Serializable;
import java.util.Date;
import javax.persistence.Basic;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.NamedQueries;
import javax.persistence.NamedQuery;
import javax.persistence.SequenceGenerator;
import javax.persistence.Table;
import javax.persistence.Temporal;
import javax.persistence.TemporalType;

/**
*
* @author S-H
*/
@Entity
@Table(name = "BRUGER")
@NamedQueries({
    @NamedQuery(name = "Bruger.findAll", query = "SELECT b FROM Bruger b"),
    @NamedQuery(name = "Bruger.findByUsername", query = "SELECT b FROM Bruger b WHERE b.username = :username")})
@SequenceGenerator(sequenceName = "WHAT_SEQ",name = "SEQ")
public class Bruger implements Serializable {
    @Basic(optional = false)
    @Column(name = "FIRSTNAME")
    private String firstname;
    @Basic(optional = false)
    @Column(name = "LASTNAME")
    private String lastname;
    @Column(name = "ADRESS")
    private String adress;
    @Column(name = "POSTNR")
    private Integer postnr;
    @Column(name = "PHONE")
    private String phone;
    @Column(name = "BIRTH")
    @Temporal(TemporalType.DATE)
    private Date birth;
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(generator = "SEQ", strategy = GenerationType.SEQUENCE)
    @Basic(optional = false)
    @Column(name = "ID")
    private Integer id;
    @Basic(optional = false)
    @Column(name = "USERNAME")
    private String username;
    @Basic(optional = false)
    @Column(name = "PASSWORD")
    private String password;
    @Basic(optional = false)
    @Column(name = "EMAIL")
    private String email;

    public Bruger() {
    }

   

    public Bruger(String username, String password, String email) {
       
        this.username = username;
        this.password = password;
        this.email = email;
    }

    public Bruger(String firstname, String lastname, String adress, Integer postnr, String phone, Date birth, String username, String password, String email) {
        this.firstname = firstname;
        this.lastname = lastname;
        this.adress = adress;
        this.postnr = postnr;
        this.phone = phone;
        this.birth = birth;
       
        this.username = username;
        this.password = password;
        this.email = email;
    }

   
    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    @Override
    public int hashCode() {
        int hash = 0;
        hash += (id != null ? id.hashCode() : 0);
        return hash;
    }

    @Override
    public boolean equals(Object object) {
        // TODO: Warning - this method won't work in the case the id fields are not set
        if (!(object instanceof Bruger)) {
            return false;
        }
        Bruger other = (Bruger) object;
        if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
            return false;
        }
        return true;
    }

    @Override
    public String toString() {
        return "dk.whatueat.JPA.Bruger[ id=" + id + " ]";
    }

    public String getFirstname() {
        return firstname;
    }

    public void setFirstname(String firstname) {
        this.firstname = firstname;
    }

    public String getLastname() {
        return lastname;
    }

    public void setLastname(String lastname) {
        this.lastname = lastname;
    }

    public String getAdress() {
        return adress;
    }

    public void setAdress(String adress) {
        this.adress = adress;
    }

    public Integer getPostnr() {
        return postnr;
    }

    public void setPostnr(Integer postnr) {
        this.postnr = postnr;
    }

    public String getPhone() {
        return phone;
    }

    public void setPhone(String phone) {
        this.phone = phone;
    }

    public Date getBirth() {
        return birth;
    }

    public void setBirth(Date birth) {
        this.birth = birth;
    }
   
}

du kan også få persistance.xml..

<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
  <persistence-unit name="WhatUEatJPAPU" transaction-type="RESOURCE_LOCAL">
    <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
    <class>dk.whatueat.model.Bruger</class>
    <properties>
      <property name="javax.persistence.jdbc.url" value="jdbc:derby://localhost:1527/whatueat"/>
      <property name="javax.persistence.jdbc.password" value="swh"/>
      <property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.ClientDriver"/>
      <property name="javax.persistence.jdbc.user" value="swh"/>
    </properties>
  </persistence-unit>
</persistence>

dk.whatueat.JPA.Bruger
dk.whatueat.model.Bruger

er ikke samme klasse

okay, det eneste sted der står dk.whatueat.JPA.Bruger det er i Bruger tostring

@Override
    public String toString() {
        return "dk.whatueat.JPA.Bruger[ id=" + id + " ]";
    }

har ændret den til .model... men nu virker det...

Fatter ikke netbeans...