:::tilfoej.php:::
<?php
mysql_connect() or die(mysql_error());
mysql_select_db();
if (isset($_POST['navn'])) {
mysql_query("insert into heste (kategori, navn, far, mor, praimie, pris, alder, tekst, billeder, stamtrae) values('".$_POST['kategori']."', '".$_POST['navn']."', '".$_POST['far']."', '".$_POST['mor']."', '".$_POST['praimie']."', '".$_POST['pris']."', '".$_POST['alder']."', '".$_POST['tekst']."', '".$_POST['billeder']."', '".$_POST['stamtrae']."')") or die (mysql_error());
echo '<div>hesten er oprettet</div>';
}
?>
<div class='txtrf' style="float: left; width: 200px;">Billede:</div>
<input type="file" name="billede"> <br />
:::view.php:::
<?php
mysql_connect() or die(mysql_error());
mysql_select_db();
// Performing SQL query
$query = 'SELECT * FROM heste';
$result = mysql_query($query) or die('Query failed: ' . mysql_error());
// Printing results in HTML
echo "<table>\n";
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "\t<tr>\n";
foreach ($line as $col_value) {
echo "\t\t<td>$col_value</td>\n";
}
echo "\t</tr>\n";
}
echo "</table>\n";
?>
::::::::::::::::::::::::::::..'
Den skriver bare stien...
