Kan du eventuelt beskrive hvad dit program skal kryptere, lidt om hvad dit program laver samt hvem det er der ikke må få adgang til oplysningerne. (der er stor forskel på om det er mod din lillebror eller hvis du er ved at lave et e-handelssystem :) )
Private Function Decrypt(PlainStr As String, key As String) Dim Char As String, KeyChar As String, NewStr As String Dim Pos As Integer Dim i As Integer, Side1 As String, Side2 As String Pos = 1
\'This is a little trick to make it slightly harder to crack. \'However, the chances of this operation firing is 50/50 \'because the length of the string must be divisable by 2. If Len(PlainStr) Mod 2 = 0 Then Side1 = StrReverse(Left(PlainStr, (Len(PlainStr) / 2))) Side2 = StrReverse(Right(PlainStr, (Len(PlainStr) / 2))) PlainStr = Side1 & Side2 End If
\'This loop decrypts the data. For i = 1 To Len(PlainStr) Char = Mid(PlainStr, i, 1) KeyChar = Mid(key, Pos, 1) NewStr = NewStr & Chr(Asc(Char) Xor Asc(KeyChar)) If Pos = Len(key) Then Pos = 0 Pos = Pos + 1 Next i
Decrypt = NewStr End Function
Private Function Encrypt(PlainStr As String, key As String) Dim Char As String, KeyChar As String, NewStr As String Dim Pos As Integer Dim i As Integer, Side1 As String, Side2 As String Pos = 1
\'This loop encrypts the data. For i = 1 To Len(PlainStr) Char = Mid(PlainStr, i, 1) KeyChar = Mid(key, Pos, 1) NewStr = NewStr & Chr(Asc(Char) Xor Asc(KeyChar)) If Pos = Len(key) Then Pos = 0 Pos = Pos + 1 Next i
\'This is a little trick to make it slightly harder to crack. \'However, the chances of this operation firing is 50/50 \'because the length of the string must be divisable by 2. If Len(NewStr) Mod 2 = 0 Then Side1 = StrReverse(Left(NewStr, (Len(NewStr) / 2))) Side2 = StrReverse(Right(NewStr, (Len(NewStr) / 2))) NewStr = Side1 & Side2 End If
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